The value of 0 . 16 log 2 . 5 1 3 + 1 3 2 + 1 3 3 +   . . .   to   is
(a) 0.16                (b) 1                  (c) 0.4                   (d) 4

Hi, Expression 13+132+133+.... is GP with a = 13 and r = 13213= 13so sum = a1-r= 131-13= 12= 0.5so 0.16log2.50.5= 0.16log0.520.5=0.1612log0.50.5=0.1612=0.4×0.4= 0.4 using property logxyr=1ylogxr

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