the value of summation r=0 to r=m of 10Cr 20Cm-r is maximum when: 5 10 15 20 Share with your friends Share 1 Rahul Raj answered this Dear student (1+x)20=C020+C120x+....+C2020x20(1+1/x)10=C010+C110(1/x)+....+C10101/x10given summation= coefficient of xr in (1+1/x)10 × coefficient of xm-r in (1+x)20=coefficient of xm in (1+x)20(1+1/x)10=coefficient of xm in (1+x)30x10=coefficient of xm+10 in (1+x)30 =Cm+1030 which is maximum when m=20 Regards 0 View Full Answer