the vapour density of a mixture containing NO2 and N2O4 is 38 3 at 27 degree celsius calculate the - Chemistry - Some Basic Concepts of Chemistry

Question

the vapour density of a mixture containing NO2 and N2O4 is 38 3
at 27 degree celsius calculate the mole of NO2 in 100
molemixture

Priya G N · Accepted Answer

Let us assume that there are x moles of NO2 in the mixture Hence,
there will be (100-x) moles of N2O4 in the mixture (since total
number of moles is 100)

We know that 1 mole of NO2 weighs 46g (14 + 2*16) and

1 mole of N2O4 weighs 92g (2*14 + 4*16)

Total molecular mass of the mixture = x*46 + (100-x)92

We also know that Molecular mass = 2 * Vapour density

= 2 * 38 3

= 76 6g

Molar mass of mixture = Mass of mixture / (Number of moles of NO2 +
Number of moles of N2O4)

Molar mass of mixture = Mass of mixture / (x + 100
â€“x)

Therefore, (46x + (100-x)92)/100 = 76 6

46x + 9200 â€“ 92x = 7660

46x = 1540

Therefore, x = 33 48 moles i e , 33 48 moles of NO2 are present in
the mixture

the vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27 degree celsius. calculate the mole of NO2 in 100 molemixture.