The vapour pressure of 2% solution of a non -volatile substance X at 373K is 755 torr.calculate the molar mass of the solute .Vapour pressure of pure water at 373K is 760 torr. Share with your friends Share 8 Geetha answered this According to lowering of vapour pressure,P0 - PP0 = W2M2 × M1W1760 -755760 = 2M2 × 1898M2 = 2 × 18 × 7605 × 98 = 55.84 g 1 View Full Answer