The x co-ordinate of the incentre of the triangle that has the co-ordinates of mid-points of its sides as (0,1) (1,1) and (1,0) is:1) 1+ $scriptstyle sqrt{2}$ 2)1- $scriptstyle sqrt{2}$ 3)2+ $scriptstyle sqrt{2}$ 4)2- $scriptstyle sqrt{2}$

Let the co-ordinates of the vertices of the triangle be.

So as we have the mid-point . So,

Solving the above we get the 3 vertices as A(0,0) B(2,0) C(0,2)

So,

So the co-ordinates of the incentre-

So the answer is option (4)

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