there were five peices of cloth o of lenghts 15 m, 21 m, 36 m, 42 m, 48 m. But all of them could be measured in hole units of a measuring rod. What could be the largest lenght of the rod.

15 = 3 × 521 = 3 × 736 = 3 × 3 × 2 × 242 = 3 × 2 × 748 = 3 × 2 × 2 × 2 × 2

HCF  = 3
Length of the longest rod = 3 m

  • 1

48m.

  • -2

right the answer is 48 m ,ok give me thumps up

  • 0

48m

  • -1
What are you looking for?