The surd 123+5+22, after rationalizing the denominator becomes(a)5-2+10+1(b)5+10+2+1(c)10+2+5+1(d)5-10-2-1 - Science - Gravitation

Question

T h e   s u r d   12 3 + 5 + 2 2 ,   a f t e r
  r a t i o n a l i z i n g   t h e   d e n o m i n
a t o r   b e c o m e s ( a ) 5 - 2 + 10 + 1 ( b ) 5 + 10 + 2
+ 1 ( c ) 10 + 2 + 5 + 1 ( d ) 5 - 10 - 2 - 1

Varun Rawat · Accepted Answer

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T h e s u r d 12 3 + 5 + 2 2 , a f t e r r a t i o n a l i z i n g t h e d e n o m i n a t o r b e c o m e s ( a ) 5 - 2 + 10 + 1 ( b ) 5 + 10 + 2 + 1 ( c ) 10 + 2 + 5 + 1 ( d ) 5 - 10 - 2 - 1

$T h e s u r d \frac{12}{3 + \sqrt{5} + 2 \sqrt{2}}, a f t e r r a t i o n a l i z i n g t h e d e n o m i n a t o r b e c o m e s (a) \sqrt{5} - \sqrt{2} + \sqrt{10} + 1 (b) \sqrt{5} + \sqrt{10} + \sqrt{2} + 1 (c) \sqrt{10} + \sqrt{2} + \sqrt{5} + 1 (d) \sqrt{5} - \sqrt{10} - \sqrt{2} - 1$