This one is hard to solve pls find solution with an explanation

Dear Student
As given kinetic energy is same for both12mAvA2 =12mBvB2 vA2vB2 =mBmA =520NowF=2 kg.wt = 2×9.8 N =19.6 NF= maaA =19.6 20 vA = u+aAtA =aAtAaB =19.6 5vB = u+aBtB =aBtBaAtA2aBtB2  =52019.6 20 tA219.6 5tB2  =5205 tA220 tB2  =520tA2 tB2  =205 =4tA tB  =2

Regards

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