This paragraph... Answers are A, B, C

Paragraph for Question 12 to 14

Let B₁ $\equiv$3x + 4y – 10 = 0 and B₂ $\equiv$4x – 3y – 5 = 0 are bisectors of angle between lines L₁= 0 and L₂ = 0. If L₁ passes through origin and L₂ = 0 meets the curve y² = 4ax at A and B.
   On the basis of above information answer the following :

Q12. Equation of line L₁ = 0 is –

       (A) x = 2y                      (B) y = 2x                 (C) x + y = 2                  (D) x – y = 4


Q13. Equation of line L₂ = 0 is –

       (A) 11x + 2y = 24         (B) 11x – 2y = 20       (C) 5x + 3y = 13            (D) 3x + 5y = 10 


Q14. If AB subtends 90° at origin then a is equal to -

       $\left(\mathrm{A}\right) \frac{4}{11} \left(\mathrm{B}\right) \frac{3}{11} \left(\mathrm{C}\right) \frac{5}{11} \left(\mathrm{D}\right) \frac{2}{11}$