Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes:

Outcomes: 3 tails   2 tails  1 tail  No tail
Frequency:    31        68       75      26    

Find the probability of getting:
  (a) at least 2 tails.
  (b) at most 2 tails.

Dear student,

Please find below the solution to the asked query:

The respective probabilities for each of the given outcome is,   Prob3 tails=31200   Prob2 tails=68200   Prob1 tails=75200   Probno tails=26200a The probability of getting atleast 2 tails is,   probatleast 2 tails=prob2 tails or 3 tails                                    =prob2 tails+prob 3 tails                                    =68200+31200                                    =99200                                    =0.495b The probability of getting atmost 2 tails is,   probatmost 2 tails=probNo tail or 1 tail or 2 tails                                    =probNo tails+prob 2 tail+prob 2 tails                                    =26200++75200+68200                                    =169200                                    =0.845


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  • 3
(a) 68/200=0.34
(b)99/200
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