# Three consecutive integers add up to 51. what are these integers? ? slove this

let the three consecutive integers be x, x-1, x+1.

ATQ

x+x+1+x+2= 51

3x= 51 -1-2

3x=48

x= 48/3

x=16

first consecutive integer=16

second consecutive integer= x+1=16+1= 17

third consecutive integer= x+1= 16+2= 18

• 1

let the three consecutive integers be x, x-1, x+1.

according to the question

x+x+1+x+2= 51

3x= 51 -1-2

3x=48

x= 48/3

x=16

first consecutive integer=16

second consecutive integer= x+1=16+1= 17

third consecutive integer= x+1= 16+2= 18

plz thumbs up

• 4

let the three consecutive integers be x, x+1, x+2

(x)+(x+1)+(x+2)=51

3x+3=51

3x=51-3=48

x=48/3

x=16

the three consecutive integers are

x=16, x+1=17, x+2=18

• 14
Let the three consecutive integers be 2x, 2x+1 and 2x +2.
Given, their sum is 51. So,

=>  2x + ( 2x + 1 ) + ( 2x + 2 ) = 51.
=>  2x + 2x + 1 + 2x + 2 = 51.
=>  6x + 3 = 51.
=> 6x = 51 - 3 =  48.
= x = 48 / 6 = 8.
So, x = 8.

First integer = 2x = 2*8 = 16.
Second integer = 2x + 1 = (2*8) + 1 = 16 +1 = 17.
Third integer = 2x + 2 = (2*8) + 2 = 16 + 2 = 18.

Therefore, the three consecutive integers are 16, 17 and 18 respectively.

You can solve it by either taking 2x as a variable or by just taking the simple x as the variable. The choice is yours, you can solve in your way.

Hope it helps !!!!
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