Three cubes each of side 3cm are joined end to end . find the surface area of the resultant cube??

Given, the edge of the cube is 3 cm.

When three cubes are joined end to end, then the resulting solid is a cuboid.

Length of the cuboid, *l *= 3 × Edge of the cube = 3 × 3 cm = 9 cm

Breadth of the cuboid, *b* = Edge of the cube = 3 cm

Height of the cuboid, *h* = Edge of the cube = 3 cm

Surface area of the cuboid

= 2 (*lb* + *bh* + *hl*)

= 2 (9 cm × 3 cm + 3 cm × 3 cm + 3 cm × 9 cm)

= 2 (27 cm^{2} + 9 cm^{2} + 27 cm^{2})

= 2 × 63 cm^{2}

= 126 cm^{2}

Thus, the surface area of the resulting cuboid is 126 cm^{2}.

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