Three cubes whose edges measure 3cm,4cm,5cm respectively to form a single cube.Find its edge.Also find the surface area of the new cube.

Volume of new cube = Sum of volume of three cubes

= 33 + 43 + 53

= 216 cm3

i.e., (edge)3 = 216 cm3

So, Edge of the single cube = 6 cm

  • 74

Given : Three cubes of metal with edges 3 cm, 4 cm and 5 cm are melted to form a new single cube

 

Let the edge of new cube be a.

⇒ Volume of new cube = Volumes of three small cubes

a 3 = (3 cm)3 + (4 cm)3 + (5 cm)3

= a3 = 27 cm3 + 64 cm3 + 125 cm3

= a3 = 216 cm3

a = 6 cm

 

Hence Lateral surface area of new cube = 6a 2

= 6 x (6 cm)2 = 6 x 36 cm2

= 216 cm2

  • 2

Volume of new cube = Sum of volume of three cubes

= 33 + 43 + 53

= 216 cm3

i.e., (edge)3 = 216 cm3

So, Edge of the single cube = 6 cm

  • -1

Given : Three cubes of metal with edges 3 cm, 4 cm and 5 cm are melted to form a new single cube

Let the edge of new cube be a.

⇒ Volume of new cube = Volumes of three small cubes

a 3 = (3 cm)3 + (4 cm)3 + (5 cm)3

= a3 = 27 cm3 + 64 cm3 + 125 cm3

= a3 = 216 cm3

a = 6 cm

Hence Lateral surface area of new cube = 6a 2

  • 3

= 6 x (6 cm)2 = 6 x 36 cm2

= 216 cm2

  • -2

Volume of new cube = Sum of volume of three cubes

= 33+ 43+ 53

= 216 cm3

i.e., (edge)3= 216 cm3

So, Edge of the single cube = 6 cm

  • 8

Total volume of 3 cubes = (3+ 4+ 5) cm3

                                   = (27 + 64 + 125)cm3

                                   = 216 cm3

Now volume of new cube = 216 cm3

So edge of new cube = cube root of 216 cm3

                               = 6 cm

  • 3
First edge = 3 cm 
Second edge= 4 cm
Third  edge = 5 cm 

VOLUME OF NEW CUBE = SUM OF VOLUME OF ALL THREE CUBES 

VOLUME = A3
V1= 3
V2=43
V3=53

V1+V2+V3=VOLUME OF NEW CUBE

27+64+125= 216cm3

Side of new cube = root of 216 (AS VOLUME = A3)
Side = 6 cm 

EDGE = 6cm 


TSA = 6a2
         = 6*(6)2
         = 6*36 
         = 216 cm2

TOTAL SURFACE AREA  = 216 CM2   EDGE = 6 CM



        
 
  • 10
The answer of this question is 6 cm.
  • 0
1 cube edge is 3 cm
2 cube edge is 4 cm
3 cube edge is 5 cm
edge of the new cube formed
volume of new cube = volume of all three cubes
volume of cube = s3
33 + 4+ 53
27 + 64 + 125
216 cm3
cube root of 216 = 6
edge of the new cube formed = 6 cm
 
  • 26
First cube edge is 3 cm
Second cube edge is 4 cm
Third cube edge is 5 cm
edge of the new cube formed
volume of new cube = volume of all three cubes
volume of cube = s3
33?+ 43?+ 53
27 + 64 + 125
216 cm3
cube root of 216 = 6
edge of the new cube formed = 6 cm
?
  • 1
idk
  • -2
6cm
  • -5
good question

  • -2
233344333334444433
  • -10
yes
  • -3
3root216=6
  • -3
6 cm
  • -2
solution,
     the sum of three cubes be,
                  33 + 43 + 53= 216 cm3
        let the edge be x.
                        x = 216 cm3
                        x  = 6cm
 
  • -1
SURFACE AREA OF A CUBE IS 6 CM
  • 1
edge=6
  • -2
In the above answer if edge 
=6cm
then,
surface area of the cube is 4 (edge square)
=4(6*6)
=36*4

=144 sq.cm


 
  • 0
Vidya wants to cover who dimensions are20cm,30cm,8cm. She has a piece of paper of area 1sqm will she able to cover a gift .explain
  • 0
here
volume of new cube=sum of all the 3 cubes
also volume of a cube=edge^3
as given
edge of 1st cube=3cm
            2nd cube=4cm
           3rd cube=5cm
therefore volume of new cube=3^3+4^3+5^3
                                                  =27+64+125
                                                  =216cm^3
also
edge of new cube: edge^3=216cm^3
                                edge=6cm
  • 2
lbh
3*4*5=60
  • -2
Given sides of all the three cubes=3 cm, 4 cm and 5 cm. Volume if new cube= Sum of volume of all the thre cubes Formula to find the volume if a cube=Side raised to the power 3 or side cube. Therefore the volume of new cube=(3 cube + 4 cube +5cube) cubic cm =(27+64+125) cubic cm =216 cubic cm
  • 4
volume of new cube = Sum of volume of three cubes
= 33 + 43 + 53
= 216 cm3
 i.e (edge)
3 = 216 cm^3
So, Edge of the single cube = 6 cm

 
  • 3
6cm
 
  • -1
sum of three cubes =volume of new cube
  • 1
a hollow hemispherical vessel has external and internal radius as 43 cm nd 42 cm respectively.if rate of colouring it is 7 paisa per cm^2 then find the coat of painting the vessel
  • -2
6m
 
  • 0
volume of new cube = sum of the volume of three cubes
=3^3+4^3+5^3
=216 cm^3
ie,(edge)^3=216cm^3
so,edge of the single cube=6cm
  • -1
volume of new cube =sum of volume of three cubes
                                  =3
  • -1
Suppose, we have three cubes of  different edges,
To form a single large cube,
The total volume of all small cubes= 33+43+53=27+64+125=216 cm3
So the edge of the larger cube is= 2161/3=6 cm
The total surface area of the larger cube is=6x2=6*36=216 cm2
Hence, the larger cube has a surface area of 216 cm2
 
  • 3
Volume of new cube = Sum of volume of three cubes = 33 + 43 + 53 = 216 cm3 i.e., (edge)3 = 216 cm3 So, Edge of the single cube = 6 cm
  • -1
volume of cube = s3
                     = 33+43+53
                     =27+64+125
                     =216cm​3
Edge=216/6/6
        =6
surface area of first cube = 6s2
                                        = 6*32
                                         = 6* 9
                                         =54
surface area of second cube=6*42
                                                    
=6*16
                                            =96
surface area of third cube=6*52
                                                 
=6*25
                                         =150

 
  • 1
 all sides are equal so the dimensions of the new cube will be the sum of volumes of the 3 cubes 
volume= a^3
so 1st cube volume = 5^3 = 125
2nd cube = 4^3= 64
3rd cube = 3^3 = 27
therefore new cube volume = 125+64+37=216
then each edges will : a^3 = 216
                                      a = root of 216 = 6cm
  • -1
why are there soo many answers ??lmao
  • -1
Cube of three things whose sides are melted 3 cm 4 centimeters and 5 centimeters to form a new cube, Find out the area and volume of the new cubes.
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Hope it helps u!!!!!
  • -1
6 cm
  • 0
Please find this answer

  • 2
Regards!!!

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Hey your's dp is nice can you be my friend.
  • -1
may be any of the above
  • 1
As they are melted to form one single cube so the volume of all the three cubes will equal to the volume of one single cube
a^3 + b^3 + c^3 = x^3 .........( where x is edge of greater cube and a,b,c are edge of smaller cube)
3^3 + 4^3 + 5^3 = x^3
9+64+125 = x^3
216 = x^3
(6)^3 = x^3
on comparing x will equal to 6 
so, edge of greater cube is equal to 6
Surface Area will equal to 6a^2
6 x (6)^2
216 cm^2
  • 0
Please find this answer

  • 0
Please find this answer

  • -1
fhjvusfufhyfsfuh
 
  • -1
Edge=6cm
Tsa=216
  • -1
Volume of 3 cubes= (3^3+4^3+5^3)

= 27+64+126
= 216

Cube root of 216 = 6 cm ( the edge of the new cube)

CSA= 4a^2
=4?6^2
=4?36
=144cm^2
=
  • -1
Sorry i dont know
  • -1
answer
  • -1
Please find this answer

  • 0
OOOKYGHUG 
  • 0
HUMM
  • 0
Edge=6
Total surface area=216sq. cm
  • 0
one book cost is 5 Rupees then there are 5 5 into 5 is equal to 25 answer
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Central bureau of investigation
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The new cube edge is 12
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(1)Diagonal of the cuboid =?l square +b square +h square
(2)Diagonal of the cube =?3a
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Edge of 1st cube = 3cm

Volume of 1st cube = edge^3

=3^3

=27cm^3

Edge of 2nd cube=4cm

Volume of 2nd cube =4^3

=64cm^3

Edge of 3rd cube =5cm

Volume of 3rd cube =5^3

=125cm^3

Total volume of the 3 cubes =Volume of new cube

Volume of new cube = 27 +64+125cm^3

=216cm^3

Edge^3=216

Edge=6cm

Surface area of the new cube = 6×edge^2

=6×6^2

=216cm^2
 
  • 1
Volume of the new cube=3^3+4^3+5^3
=27+64+125
=216
Length of the edge of the new cube=3?216
=6 cm
TSA of the new cube=6?6^2
=216
  • 0
LSA of the new cube=4?6^2
=4?36
=144 cm^2
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Please find this answer

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????? ????? ??? ??? ???? ??
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What is set Ask me
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What is set Ask me
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I understand
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Please find this answer

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Volume of new cube = Sum of volume of three cubes
= 33 + 43 + 53
= 216 cm3
i.e., (edge)3 = 216 cm3
So, Edge of the single cube = 6 cm
Your Welcome!!!!!!!!!!!

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Tanu Kumari 2020
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Rohit kumar
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Hosur Medhavi Ashish Mankar
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A Textbook Of Mathematics ka book sa 8.1 8.2 bala math solusion
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Please find this answer

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Image answer

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The find attached my answer is twelve
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Sorry my answer six
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Please find this answer

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1 cube edge is 3 cm
2 cube edge is 4 cm
3 cube edge is 5 cm
edge of the new cube formed
volume of new cube = volume of all three cubes
volume of cube = s3
33 + 43 + 53
27 + 64 + 125
216 cm3
cube root of 216 = 6
edge of the new cube formed = 6 cm
  • 0
9th standent question paper
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Volume of a new cube = Sum of volumes of three cubes
= 33?+ 43?+ 53
= 216 cm3
(edge)3?= 216 cm3
So, Edge of a single cube = 6 cm
  • 0
Please find this answer

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5055
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Please find this answer

  • 0
Ans is volume of cube is = l ?b?h
3?4?5?=60
And then
Surface area of cube= 6?(l)power 2
6?(60) power 2
=6?3600
=21600
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Please find this answer

  • 0
Answer - 144cm^2

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Length of each side of cube /= cm
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Answer would be edge of new cube=6cm
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