Three friends plucked some mangoes from a mango groove and collected together in a pile and took nap after that. After some time one of the friends woke up and divided the mangoes into three equal numbers. There was one mango extra. He gave it to a monkey nearby and took one part for himselfand slept again. Next the second friend got up unaware of what had happened, divided the rest of mangoes into three equal shares. There was mango extra. Hd gave it to a monkey nearby, took one share for himself and slept again. Next the third friend got up not knowing whay had happened and divided the mangoes into three equal shares. There was one extra mango. He gave it the monkey, took one share for himself and went to sleep again. After some time, all of them got up together to find 30 mangoes. How many mangoes did the friends pluck initially? Please explain the process too. I request the meritnation experts to please answer my query.

this can be easily solved in the reverse order.

let the number of mangoes , when third friend got up be x+1.

one mango he has given to the monkey.

therefore he has taken x/3 mangoes.

the remaining mangoes are 2x/3

2x/3 = 30

x = 30*3/2 = 45

thus the number of mangoes when 3rd friend got up is 45+1 = 46.

similarly let the number of mangoes when 2nd friend got up be y+1.

therefore

2y/3 = 46

y = 46*3/2 = 69

thus the number of mangoes when 2nd friend got up = 69+1 = 70

let the number of mangoes , when first friend got up be z+1 (i.e. the number of mangoes which they pluck initially)

2z/3 = 70

z = 70*3/2 = 105

therefore the total number of mangoes = 105+1 = 106

hope this helps you.

cheers!!

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