Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip?

**[{**i have read the solution for this but i am not understanding**}]**

Let A denotes position of Reshma, B denotes position of Salma and C denotes position of Mandip.

Here,

AB = BC = 6 m and

OA = OB = OC = 5 m (radius)

Draw perpendiculars OM and ON on AB and BC respectively.

In ΔOAM,

OM^{2} + AM^{2} = OA^{2}

OM^{2} + (3)^{2} = (5)^{2}

OM^{2} = (25 − 9) m^{2} = 16 m^{2}

OM = 4 m

OABC will be a kite (OA = OC and AB = BC).

As, we know that the diagonals of a kite are perpendicular and the diagonal common to both the isosceles triangles is bisected by another diagonal.

∴∠AXB will be of 90° and AX = XC

Area of ΔOAB =

∴the distance between Reshma and Mandip = 9.6 m

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