Three identical capacitors C 1 , C 2 and C 3 of capacitance 6 μ F each are connected to a 12 V battery as shown.
Find
(i) charge on each capacitor
(ii) equivalent capacitance of the network
(iii) energy stored in the network of capacitors
Hi Sanal!
The solution to the problems is as follows:
(i) Charge on each capacitors:
The capacitors C1 and C2 are in series. Therefore the equivalent capacitance of this combination is 
As you know, charge Q= CV.
Therefore charge on C1= charge on C2=3µF×12V=36µC.
Charge on C3=6µF×12V=72µC.
(ii) Equivalent capacitance of the network:
The equivalent capacitance of the series combination of C1 and C2 is 3µF. This is in parallel with C3. Therefore, the equivalent capacitance of the network Ceq=3µF+ 6µF =9µF.
(iii) Energy stored in the network of capacitors:
Cheers!!