three particles each of mass m gram, are situated at the vertices of an equilateral trangle ABC of side l cm The moment of inertia of the system about a line AX perpendicular to AB and in the plane of ABC will be

Dear Student,

The moment of inertia about the line AX, IAX=ml2+md2We know that,sinθ=perpendicularhypotenusesin30°=dl12=dld=l2Therefore, IAX=ml2+ml22IAX=ml2+ml24IAX=5ml24

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