To code 50 amino acids in a polypeptide chain what will be the minimum number of nucleotides in its cistron ?
Dear student,
To code 50 amino acid, we need 50 codons for amino acid plus one as stop codon.
One codon consist of three nucleotides, therefore, total codon required is 51*3=153
Cistron is double stranded, therefore, total nucleotide=153*2=306
Regards
To code 50 amino acid, we need 50 codons for amino acid plus one as stop codon.
One codon consist of three nucleotides, therefore, total codon required is 51*3=153
Cistron is double stranded, therefore, total nucleotide=153*2=306
Regards