to construct a triangle to a given triangle ABC with sides 8/5 of the corresponding sides of triangle ABC, draw a ray BX such that angle CBX is an acute angle and X is on the opposite side of A with respect to BC. the minimum number of points to be located at equal distances on ray BX is -----------------
a) 13 b) 8
explain the answer plzzzz.
what would the answer be if ratio was 5/8 instead of 8/5 ?
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1)After drawing triangle ABC ,draw an acute angle CBX below BC .
2)Along BX ,mark off 8 points at equal distances .
3) Join to C and draw a line parallel to intersecting BC extended at C'.
4) Draw a line through C' parallel to CA intersecting BA extended at A'.
Thus A'BC' is the required triangle .
Now if the ratio is instead of then also you have to mark off 8 points but the difference is that in this case you have to join to C