# to construct a triangle to a given triangle ABC with sides 8/5 of the corresponding sides of triangle ABC, draw a ray BX such that angle CBX is an acute angle and X is on the opposite side of A with respect to BC. the minimum number of points to be located at equal distances on ray BX is -----------------a) 13 b) 8explain the answer plzzzz.what would the answer be if ratio was 5/8 instead of 8/5 ?explain?fast i'll give u a thumbs up!!!

Steps of  constructing  a triangle similar to the given triangle ABC with sides $\frac{8}{5}$ of the corresponding sides of triangle ABC .
1)After drawing triangle ABC ,draw an acute angle CBX below BC .
2)Along BX ,mark off 8 points at equal distances .
3) Join ${B}_{5}$ to  C and draw a line ${B}_{8}$  parallel to ${B}_{5}C$ intersecting BC extended at C'.
4) Draw a line through C' parallel to CA intersecting BA extended at A'.
Thus A'BC' is the required triangle .

Explanation:-

Now if the ratio is $\frac{5}{8}$ instead of $\frac{8}{5}$ then also you have to mark off 8 points but the difference is that in this case you have to join ${B}_{8}$ to C

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