Triangles ques aol plz

  • 0
In triangle ABC, PQR
AB = PQ = 10cm
BC = QR = 6cm
angle ABC = angle PQR = 51 degrees
So ABC = PQR (SAS test)

SO angle BAC = QPR (CPCTC)

40 - x = 4x - 10
5x = 50
x = 10

So the angle is 40 - x = 40 - 10 = 30
So angle QPR = 30
  • 0
What are you looking for?