Two bodies of mass 4 and 6 kg are attached to the ends of a string passing over a pulley. The 4 kg mass is attached to the table top by another string. Find the tension in the string T1. (g=9.8 m/s2).
T - 4g = 4a --------equation 1
-T +6g = 6a --------equation 2
Solving these two equations, we get
2g = 10a
2(9.8)=10a
a = 1.96m/s^2
T1=ma
m = 4+6=10kg
T1=10(1.96) = 19.6N
-T +6g = 6a --------equation 2
Solving these two equations, we get
2g = 10a
2(9.8)=10a
a = 1.96m/s^2
T1=ma
m = 4+6=10kg
T1=10(1.96) = 19.6N