Two circles are drawn with sides AB and AC of a triangle ABC as diameters. The circles intersect at a point D. If AB=5 cm, BD=3 cm , AC= 6 cm. Find BC Share with your friends Share 6 Lovina Kansal answered this Dear student Join AD.Since angle in a semi-circle is a right angle.Therefore, ∠ADB=∠ADC=90°Now, In △ADB by Pythagoras theroemAB2=AD2+BD2⇒52=AD2+32⇒AD2=25-9⇒AD=4cmIn △ADC, by Pythagoras theoremAC2=AD2+DC2⇒62=42+DC2⇒DC2=36-16⇒DC=20⇒DC=25So, BC=BD+DC=3+25cm Regards 6 View Full Answer