two cross roads , each of width 5m , run at right angles through the centre of a rectangular park of 70m and breadth 45m and parallel to its sides. find the area of roads ; also find the cost of constructing the roads at the rate of Rs . 105 per square m. please answer me fast.

The figure below shows two cross roads JKLM and PQRS inside a rectangular park ABCD;

Length of rectangular park; AB = 70 m
And breadth of park; AD = 45 m
Width of road = PQ = JK = 5 m
And PS = AB = 70 m and JM = AD = 45 m
Area of road PQRS = $\mathrm{PS}\times \mathrm{PQ} = 70\times 5 = 350 {\mathrm{m}}^2$
And area of road JKLM = $\mathrm{JM}\times \mathrm{JK} = 45\times 5 = 225 {\mathrm{m}}^2$
area of common region WVUT = $5\times 5 = 25 {\mathrm{m}}^2$
So total area of cross roads = $\left(350 {\mathrm{m}}^2+225 {\mathrm{m}}^2\right)-25 {\mathrm{m}}^2 = 550 {\mathrm{m}}^2$
Now cost of constructing the roads per metre square = Rs.105
Therefore total cost of constructing the road = $550\times 105$ = Rs.57750