# two dice are thrown at the same time .find the probability of getting different numbers on both dice?

if two different dice are thrown , the number of possible outcomes =

the number of outcomes when both the dice show same number = {(1, 1) , (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)}

i.e.  6 outcomes

the number of outcomes getting different number on both dice = 36 - 6 = 30

the required probability =

hope this helps you.

cheers!!

• 56

total possible outcomes = 36

possible outcoms for getting same numbers on both dice = (1,1), (2,2), (3,3), (4,4), (5,5), (6,6) = 6

thus possible outcomes for getting different numbers = 36 - 6 = 30

thus probability of getting different numbers on both dice = 30/36 =5/6

hope u got it.............

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• 11

When two dice are thrown at the same time.. then the possible outcomes are

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

total possible outcomes = 36
possible outcoms for getting same numbers on both dice = (1,1), (2,2), (3,3), (4,4), (5,5), (6,6) = 6
probability of getting different numbers on both dice = 30/36 =5/6

• 4

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

total possible outcomes = 36

possible outcoms for getting different numbers on both dice =30

probability of getting different numbers on both dice = 30/36