two dice are thrown together . find the probability of that the product of the numbers on the top of the dice is (a)6 (b)12 (c( 7

aGiven, two dice are thrown together. So, total number of outcomes=6×6=36Favourable cases of getting the product of the number on the top of the dice 6=2,3,3,2,6,1,1,6 Total number of favourable cases=4Probability of getting the product of the number on the top of the dice 6 =Total number of favourable casesTotal number of outcomes=436=19bFavourable cases of getting the product of the number on the top of the dice 12 =4,3,3,4,6,2,2,6 Total number of favourable cases=4Probability of getting the product of the number on the top of the dice 12 =Total number of favourable casesTotal number of outcomes=436=19cFavourable cases of getting the product of the number on the top of the dice 7=0 Total number of favourable cases=0 Probability of getting the product of the number on the top of the dice 7 =Total number of favourable casesTotal number of outcomes=036=0

  • 36

p(of getting 6)=(2,3) ,(3,2) ,(1,6) , (6,1)=4/12=1/3

p(of getting 12)=(2,6), (3,4) , ( 4,3), (6,2)=4/12=1/3

p(of getting 7)=0

  • -6
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