Two girls, each of weight 500 N climb up a rope through a height of 6 m. We name one of
the girls A and the other B. Girl A takes 20 s while B takes 50 s to accomplish this task.
Which girl expends more power?

Solution:
Power,
P=mght=Wht    W=mgSo, power expends by girl A:PA=WAhtA =500×620=150 WPower expends by girl B:PB=WBhtB =500×650=60 WPA>PB
Hence, girl B expends more power.

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