Two identical bulbs A and B are design for some voltage. Their power ratings are PA and PB respectively, where PB > PA. They are joined in series across a V voltage supply, then which bulb will draw more power.
Dear student,
The two identical bulbs are connected in series and they have power ratings were PB>PA.
We know that P=VI.
They are designed to have the same voltage and are connected in series across a V voltage supply, so, the P will be directly proportional to I.But, the current drawn by the bulb is not mentioned in the question. So, on the basis of the power rating, the more amount of current will be drawn by the bulb having more power rating value. Hence, the power drawn by B bulb will be more than power drawn by the A bulb.
Regards
The two identical bulbs are connected in series and they have power ratings were PB>PA.
We know that P=VI.
They are designed to have the same voltage and are connected in series across a V voltage supply, so, the P will be directly proportional to I.But, the current drawn by the bulb is not mentioned in the question. So, on the basis of the power rating, the more amount of current will be drawn by the bulb having more power rating value. Hence, the power drawn by B bulb will be more than power drawn by the A bulb.
Regards