Two lines are given to be parallel. The equation of one of the lines is 4x + 3y = 14. Find the equation of the second line.
We know if we have two parallel lines a1x + b1y + c1 = 0 And a2x + b2y + c2 = 0 , Then the value of all cofficient are As :
Here we have a line 4x + 3y = 14 , So a1 = 4 , b1 = 3 and c1 = - 14
let our line that is parallel to given line is a2x + b2y + c2 = 0 , So
a2 : b2 = 4k : 3k ( Where k is a ratio constant that could be any integer )
We can form any equation that has the co efficients in the ratios 4k : 3k : n (where n is any integer and n 14k)
Our parallel equation could be
8x + 6y = 12 ( Ans )