two points A and B on a highway are at a distance of 240 km from each other. the car which startsfrom A moves with a constant speed along the direction AB and the second car moves from B at thesame time with a constant speed in the same direction. the first car overtakes the secondcar in four hours. however the second car moves from Btowards A then the car meet each other after 2 years. finf the speed of the car which starts fromB.
let the speed of the car which starts from point A be x km/hr and
the speed of the car which starts from point B be y km/hr
distance AB = 240 km.
if both the cars move in same direction AB, the first car overtakes the second car in 4 hrs.
therefore distance covered by first car in 4 hrs is 240 km more to the distance covered by second car .
distance = speed * time
if they move towards each other , they meet in 2 hrs.
therefore distance covered by first car and second car in 2 hrs is equal to 240 km
subtracting eq(1) from eq(2):
thus the speed of the car which starts from B is 30 km/hr
hope this helps you.
cheers!!