Two small particles of mass m each are placed at the vertices A and B of a right angle isoceles triangle right angled at C. If AB=l, find the gravitational field strength at C
Gravitational field strength :
It is the force acting on a unit mass at the given point in a gravitational field (of another mass).
Here, G is universal gravitational constant, m is mass of the source of gravitational field,
d is distance between the given point and source of the gravitational field.
Length of the sides of right angled isosceles triangle:
From Pythagoras theorem,
Gravitational field strength due to mass at point C due to mass at point A:
Direction: Towards A (Upward)
Gravitational field strength due to mass at point C due to mass at point B:
Direction: Towards B (Right side)
Net gravitational field strength at point C:
The angle between and is 90 degrees.
Hence, net gravitational field strength is,
Answer:
Gravitational field strength at point C is,
It is the force acting on a unit mass at the given point in a gravitational field (of another mass).
Here, G is universal gravitational constant, m is mass of the source of gravitational field,
d is distance between the given point and source of the gravitational field.
Length of the sides of right angled isosceles triangle:
From Pythagoras theorem,
Gravitational field strength due to mass at point C due to mass at point A:
Direction: Towards A (Upward)
Gravitational field strength due to mass at point C due to mass at point B:
Direction: Towards B (Right side)
Net gravitational field strength at point C:
The angle between and is 90 degrees.
Hence, net gravitational field strength is,
Answer:
Gravitational field strength at point C is,