Two workers A and B working together completed a job in 5 days. If A worked twice as efficiently as he actually did and B worked 1/3 as efficiently as he actually did, the work would have been completed in 3 days. Find the time taken by A alone to complete the work?

Let A completes the work in *x* days

and B completes the work in *y* days

So, Work of A in 1 day

and work of B in 1 day

and so work of A and B in 1 day

According to question,

If A worked twice as efficiently as he actually did and B worked as efficiently as he actually did, the work would have been completed in 3 days.

So, A will complete the work in days

and B will complete the work in 3*y* days.

Multiplying (1) by 2 and then subtracting (2) from it–

∴ From (1), we get –

Hence, A takes days i.e., days to complete the work.

**
**