"Two years later a father will be 8 years more than three times the age of the son "Taking the present age of father and son as x and y respectively. Write a linear equation for teh above.Find the age of the father when son is 10 years old

Hi!

Here is the answer to your question.

Suppose, present age of father =

*x*years and present age of son =*y*yearsTwo years later,

Age of father = (

*x*+ 2) yearsAge of son = (

*y*+ 2) yearsTwo years later, age of father = 3 × Age of son + 8 years [Given]

When age of son,

*y*= 10 years, age of father,*x*= 3 × 10 + 12 = 30 + 12 = 42 yearsCheers!

**
**