Use Kirchhoff's rules to determine the potential difference between points A and D when no current flows in the arm BE of the network shown .

Dear student,

Applying kirchoffs law in circuit AFEBA,
If current I follows through circuit,
$$\begin{gathered} 2I+3I+R_1{I}_1=6-1-1 \\ 5I+R_1{I}_1=4 \end{gathered}$$
As no current flows through arm BE, I₁=0.
I=0.8 A.
Current through resistance R is 0.8A
The potential difference across AD is 2V.

Regards.