Using binomial theorem prove that (32n+2- 8n - 9) is divisible by 64,where n is a positive integer. Please give me the solution of this as soon as possible. Thank u.

In order to show that 32n+2- 8n- 9 is divisible by 64, it has to be proved that,

, wherekis some natural number and

32n+2= 32.(n+1)= 9n+1..... (1)

By Binomial Theorem,

Fora= 8 andm=n+ 1, we obtain

⇒32n+2- 8n- 9 = 64k[using (1)]

Thus,32n+2- 8n- 9 is divisible by 64, whenevernis a positive integer.

  • -1

In order to show that 32n+2- 8n- 9 is divisible by 64, it has to be proved that,

, wherekis some natural number and

32n+2= 32.(n+1)= 9n+1..... (1)

By Binomial Theorem,

Fora= 8 andm=n+ 1, we obtain

⇒32n+2- 8n- 9 = 64k[using (1)]

Thus,32n+2- 8n- 9 is divisible by 64, whenevernis a positive integer.

  • -1

In order to show that 32n+2- 8n- 9 is divisible by 64, it has to be proved that,

, wherekis some natural number and 32n+2= 32.(n+1)= 9n+1..... (1)

By Binomial Theorem,

Fora= 8 andm=n+ 1, we obtain

⇒32n+2- 8n- 9 = 64using (1)]

Thus,32n+2- 8n- 9 is divisible by 64, whenevernis a positive integer.

  • 0

thank u vidyullata :)

  • 1

wlcum

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