using factor theorem, find the value of 'a', if 2x4-ax3+4x2-x+2 is divisible by 2x+1
By remainder theorem we have,
2x + 1 = 0
2x = -1
x = -1/2
p(x) = 2x4 - ax3 + 4x2 - x + 2
p(-1/2) = 2 * (-1/2)4 - a * (-1/2)3 + 4 * (-1/2)2 - (-1/2) + 2
= 2 * 1/16 + a/8 + 1 + 1/2 + 2
= 1/8 + a/8 + 1/2 + 3
= a/8 + (1 + 4 + 24)/8
= a/8 + 29/8
By factor theorem we have,
p(x) = 0
=> a/8 + 29/8 = 0
=> a/8 = -29/8
=> a = (-29 * 8)/8
=> a = -29
Hence, by factor theorem value 'a' is -29.
2x + 1 = 0
2x = -1
x = -1/2
p(x) = 2x4 - ax3 + 4x2 - x + 2
p(-1/2) = 2 * (-1/2)4 - a * (-1/2)3 + 4 * (-1/2)2 - (-1/2) + 2
= 2 * 1/16 + a/8 + 1 + 1/2 + 2
= 1/8 + a/8 + 1/2 + 3
= a/8 + (1 + 4 + 24)/8
= a/8 + 29/8
By factor theorem we have,
p(x) = 0
=> a/8 + 29/8 = 0
=> a/8 = -29/8
=> a = (-29 * 8)/8
=> a = -29
Hence, by factor theorem value 'a' is -29.