value of p if x+1/2 is a factor of px raised to 2 - 4px + 3 Share with your friends Share 1 Varun.Rawat answered this We have,fx = px2 - 4px + 3Since, x + 12 is a factor of fx, then by factor theorem f-12 = 0⇒p-122 - 4p-12 + 3 = 0⇒p4 + 2p + 3 = 0⇒p + 8p + 124 = 0⇒9p = -12⇒p = -129 = -43 3 View Full Answer Nitesh Duraivel answered this If x + 1/2 is a factor of the polynomial px2 - 4px + 3. Then, x = -1/2. p(x) = p(x)2 - 4px + 3 p(-1/2) = p(-1/2)2 - 4p(-1/2) + 3 p(-1/2) = p/4 + 2p + 3 Now we know that since x + 1/2 is a factor of the polynomial . p/4 + 2p+ 3 = 0 p + 4(2p) + 4(3)/4 = 0 p + 8p + 12 = 0 9p = -12 p = -12/9 p = -4/3. Hope u found this answer helpful.. Thumbs up if u like this answer. 4
