value of x if log10(x-3)/log10(x2-21)=1/2 Share with your friends Share 3 Lovina Kansal answered this Dear student log10x-3log10x2-21=12⇒2 log10x-3=log10x2-21⇒log10x-32=log10x2-21⇒x-32=x2-21 ∵logbf(x)=logbg(x)⇒f(x)=g(x)⇒x2+9-6x=x2-21⇒-6x=-30⇒x=5 Regards 5 View Full Answer
