very urgent

Let f(x) = 1-tanx/4x-pi, x not equal to pi/4, x belongs to [0 , pi/2) is continuous in [0, pi/2) then f(pi/4), is

Question

very urgent

Let f(x) = 1-tanx/4x-pi, x not equal to pi/4, x belongs to [0 ,
pi/2) is continuous in [0, pi/2) then f(pi/4), is

Brijendra P. · Accepted Answer

Given, fx=1-tanx4x-πNow for finding the value when x tends to π4
limx→π41-tanx4x-π, since it is 0/0 form and hence using L'hospital rule , we get limx→π4ddx1-tanxddx4x-π=limx→π4-sec2x4=-sec2π44=-12

very urgent Let f(x) = 1-tanx/4x-pi, x not equal to pi/4, x belongs to [0 , pi/2) is continuous in [0, pi/2) then f(pi/4), is

very urgent

Let f(x) = 1-tanx/4x-pi, x not equal to pi/4, x belongs to [0 , pi/2) is continuous in [0, pi/2) then f(pi/4), is