# very urgentQ1: The function f:a to b defined by f(x) = - x2+6x - 8 is a bijection if a and b belongs to which intervalQ2: If f(4) = 4 , f*(4) = 1 then lim x tends to 4 2-​​√f(x) / 2 -​√x is equal to

the graph of the given function is as follows:

if we draw a line from the vertex parallel to y-axis, the given curve is divided into two parts

(2):

$=\frac{\mathrm{f}\text{'}\left(4\right)}{\sqrt{\mathrm{f}\left(4\right)}.\sqrt{4}}\phantom{\rule{0ex}{0ex}}=\frac{1}{\sqrt{4}*2}\phantom{\rule{0ex}{0ex}}=\frac{1}{2*2}=\frac{1}{4}$

hope this helps you

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