water flows out through a circular pipe whose internal diameter is 2cm at the rate of 0.8m/s into a cylindrical tank, the radius of whose base is 40cm. by how much will the level rise in one and half hour?
Given, internal diametre of circular pipe = 2 cm
So, radius of circular pipe = 2/2 cm = 1cm
Since water flows at the rate of 0.8 m/s.
i.e., in 1 second it covers distance = 0.8 m = 80 cm
Given, radius of cylindrical tank (r) = 40 cm
Let the increase level of water = h cm
Since, water flows out through a circular pipe at the rate of 0.8 m/s into a cylindrical tank. So,
Hence, water rise by 270 m.