# What are the 7 Laws of Exponents ?

• laws of exponent.
1. bn x bm = bn+m.
2. ac / av = ac - v
3. (am)n = anm
4. as x bs = (ab)s
5. ao  = 1
6. as / bs = (a/b)s
7. (a+b)2 = a2 + 2ab + b2
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4 as x bs = (ab)s

5  ao = 1

6  am / bm = (a/b)m

7 (a+b)2 = a2 = 2ab + b2

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sorry for the mistake

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aX an = am+n

(am)n = amn

am X bm = (ab)m

am/a= 1/am-n

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amx an= a( m + n )

am÷ an= a( m - n )

( am)n= a(m x n )= amn

a0= 1

a1= a

a-m = 1/am (1/a-m = am ) reciprocal

amx bm= (ab)m

am÷ bm= (a/ b)m

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Ism preparing for maths quant for mba entence exam my maths is weak please help me out what to do

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VBVCBNYGU7658JJYER7DSRW
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why not
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• am  x  an = am +n
• a/ an = am - n
• (am)n = amn
• am  x  bm = (ab)m
• am / bm = (a / b)m
• (a + b)2 = a2 + 2ab + b2
• a0 = 1
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Look Pravan's Ans.:-)
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Laws of Exponents :- • 3
1) (a/b)^m=(a/b)^m+n
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What is xxx
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This are the 7 Laws of Exponents. • 0 hope this helps u !

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bracket 1 upon 7 bracket close to divide bracket 1.7 bracket close power files
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### aising a Quotient to a power

When a product is raised to a power, you distribute the power to each term in the product

## 7 Laws of Exponents

Any number to the zero power besides 0, equals 1.

### Zero as an exponent.

When the bases are the same you subtract the exponent and simplify the fraction if needed.

## base.

Distribute the power over each term in the quotient.

## If an exponent is negative put the integer under 1 for division. Same if there is a negative exponent on the bottom of a fraction, bring it up and it turns positive.

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• laws of exponent.
1. bn x bm = bn+m.
2. ac / av = ac - v
3. (am)n = anm
4. ax bs = (ab)s
5. ao  = 1
6. a/ bs = (a/b)s
7. (a+b)2 = a2 + 2ab + b
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Have this!! • 0
Hello
1.a^m*a^n=a^m+n
2.a^m/a^n=a^m-n
3.a^m*b^m=(ab)^m
4.a^0=1
5.square root of a=a^1/2
6.n root of a=a^1/n
7.a^-m=1/a^m
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cheers!

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4 as x bs = (ab)s

5  ao = 1

6  am / bm = (a/b)m

7 (a+b)2 = a2 = 2ab + b2

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• laws of exponent.
1. bn x bm = bn+m.
2. ac / av = ac - v
3. (am)n = anm
4. as x bs = (ab)s
5. ao  = 1
6. as / bs = (a/b)s
7. (a+b)2 = a2 + 2ab + b2
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they are correct
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Yes i can
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. Dear students there are only for laws of exponents not seven laws of
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(X2)6
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Exponent and Power
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aX a= am+n

(am)n = amn

aX b= (ab)m

am/a= 1/am-n

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Hello
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Pis solve it for me
Approximate the followin g to 3sf 0.00729671
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Okay....
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