What is semi perimeter

Semi Perimeter:

The semi perimeter of a single closed figure is half of its perimeter. and the perimeter of a single closed figure is the length of its boundary.

Let the  perimeter of any single closed figure = 20 units.

Thus, the semi perimeter  = 20 /2 = 10 units.

  • 2

 Semi perimeter(s) of a triangle is half of its perimeter.

Consider a triangle ABC whose length of sides are a cm, b cm and c cm respectively.

⇒ 

  • 2

The semiperimeter on a figure is defined as

 s=1/2p,
(1)

where p is the perimeter. The semiperimeter of polygons appears in unexpected ways in the computation of their areas. The most notable cases are in the altitudeexradius, and inradius of a triangle, the Soddy circlesHeron's formula for the area of a triangle in terms of the legs ab, and c

 A_Delta=sqrt(s(s-a)(s-b)(s-c)),
(2)

and Brahmagupta's formula for the area of a quadrilateral

 A_(quadrilateral)=sqrt((s-a)(s-b)(s-c)(s-d)-abcdcos^2((A+B)/2)).
(3)

The semiperimeter also appears in the beautiful l'Huilier's theorem about spherical triangles.

TriangleSemiperimeter

For a triangle, the following identities hold,

s-a=1/2(-a+b+c)
(4)
s-b=1/2(+a-b+c)
(5)
s-c=1/2(+a+b-c).
(6)

Now consider the above figure. Let I be the incenter of the triangle DeltaABC, with DE, and F the tangent points of the incircle. Extend the line BA with GA=CE. Note that the pairs of triangles (ADI,AFI)(BDI,BEI)(CFI,CEI) are congruent. Then

BG=BD+AD+AG=BD+AD+CE
(7)
=1/2(2BD+2AD+2CE)
(8)
=1/2[(BD+BE)+(AD+AF)+(CE+CF)]
(9)
=1/2[(BD+AD)+(BE+CE)+(AF+CF)]
(10)
=1/2(AB+BC+AC)
(11)
=1/2(a+b+c)
(12)
=s.
(13)

Furthermore,

s-a=BG-BC
(14)
=(BD+AD+AG)-(BE+CE)
(15)
=(BD+AD+CE)-(BD+CE)
(16)
=AD
(17)
s-b=BG-AC
(18)
=(BD+AD+AG)-(AF+CF)
(19)
=(BD+AD+CE)-(AD+CE)
(20)
=BD
(21)
s-c=BG-AB
(22)
=AG
  • 1
What are you looking for?