what is the lenght of longest pole that can be put up in a room of dsimensions 10m *`10m*5m

Given that: length (l) = 10 m, Breadth (b) = 10 m and height (h) = 5 m

It is a cuboid, and longest length of a cuboid = diagonal of cuboid

Therefore,

Hence, length of longest pole is 15 m.

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The largest pole that can be put in the room = Diagonal of the room

Therefore, diagonal of the room = scriptstyle sqrt{,,}  l2 + b2 + h2

                                                   =  root of 102 + 102 + 52

                                                   = root of 100 + 100 + 25                                                                                                     =

                                                   = root of 225 = 15cm 

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The largest pole that can be put in the room = Diagonal of the room

Therefore, diagonal of the room =  scriptstyle  sqrt{ , ,}  l 2 + b2 + h2

= root of 102 + 102 + 52

= root of 100 + 100 + 25 

= root of 225 = 15cm

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the largest pole=diagonal of the room

so,diagonal=under root l square+b square+h square=10sq.+10sq.+5sq.=root of100+100+25=125root=15cm.

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