# WHAT IS THE NUMBER OF MOLES OF ALUMINIUM OXIDE FORMED WHEN 6.75g OF ALUMINIUMIS MADE TO REACT WITH 8g OF OXYGEN.IS I/8MOLE THE RIGHT ANSWER?

1. The reaction for the formation of Aluminium Oxide is as follows:

4 Al + 3 O2 $\to$ 2 Al2O3

4 moles of Aluminium reacts with 3 moles of Oxygen to give 2 moles of Aluminium Oxide.

2. Number of moles of Al =
Number of moles of O2$\frac{8}{32}=0.25$
Here Oxygen is the limiting reagent.

3. 0.25 moles of O2 reacts give

So, $\frac{1}{8}$ is not correct.

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