Which is the correct option

Solution,
When the amount of distance covered along a straight line by the object in a fixed time interval is same, then the object is said to be moving with uniform velocity and its motion is called uniform motion.
Velocity is defined as rate of change of displacement.
$v=\frac{dx}{dt}$
For straight line motion, it can also be expressed as:
$$\begin{gathered} v=\frac{x_2-x_1}{t_2-t_1} \\ where, \\ {x}_1 is the position of the object in time t_1. \\ {x}_2 is the position of the object in time t_2. \end{gathered}$$

In all the above data, the variation in time interval is uniform, i.e., $t_2-t_1=t_3-t_2=1s$
So, the data in which, the corresponding intervals of position remains fixed or constant will show uniform motion,
i.e.,
$x_2-x_1=x_3-x_2$
In option (3),
$x_2-x_1=x_3-x_2=2$
Thus, the velocity in this case is constant and has a value
​​​​​$v=\frac{x_2-x_1}{t_2-t_1}=\frac{2m}{1s}=2m/s$
Thus, the correct option is (3).
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