Which option would be correct ???? Share with your friends Share 0 Anshu Agrawal answered this Dear student, Considering both blocks as a system, Total mass of the system M = 3 kg So, net external force for the system = 3 N (as the table is frictionless) F = Ma => 3 = 3a => a = 1 ms−2 Now considering the block of 1 kg : a = 1 ms−2 (acceleration of the 1 kg block is same as the acceleration of the system) so, F = ma => F = 1 kg x 1 ms−2 = 1 N Regards 0 View Full Answer
