While finding area of triangles in coordinate geometry chapter, sometimes we get area in NEGATIVE values. Then what should we do?(example is in the pic)
B C D x 1 = 3   ,   x 2 = - 3   ,   x 3 = 2 y 1 = - 2   ,   y 2 = - 5   ,   y 3 = 3 A r e a = 1 2 x 1 y 2 - y 3 + x 2 y 3 - y 1 + x 3 y 1 - y 2                   = 1 2 3 - 8 + - 3 5 + 2 3                   = 1 2 - 24 - 15 + 6                     = - 33 2   u n i t 2

Dear student,

In such answers we neglect the -ve sign of the answer as the area can't be -ve.

Regards

 

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You have to take the mod value of (i.e positive value ) of the answer.
You are getting a negative answer because the placement of points(vertices) is in different quadrants, but area cant be negative. So take the positive value of the answer.
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