Why is 11 year old and has 80% of his full height he is 120 CM tall calculate his height at the end of his growth period
Dear student,
See take the full height of him as 'X'
So it's given, that he has had his 80% growth, and that's 120cm.
Hence,
80 % of 'X'= 120
(80÷100) × X= 120 [ 80 is divided by hundred as percent is there and it is multiplied by X]
So 0.8 × X= 120 [ It's 0.8 as 80 is divided by 100]
X= 120 ÷0.8
X=150
Therefore the full growth of the boy is 150 cm.
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
See take the full height of him as 'X'
So it's given, that he has had his 80% growth, and that's 120cm.
Hence,
80 % of 'X'= 120
(80÷100) × X= 120 [ 80 is divided by hundred as percent is there and it is multiplied by X]
So 0.8 × X= 120 [ It's 0.8 as 80 is divided by 100]
X= 120 ÷0.8
X=150
Therefore the full growth of the boy is 150 cm.
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards