# without doing actual division, find the remainder when; 981547 is divided by 5 51439786 is divided by 3 798 is divided by 11 also write the steps to find the ans.

1.

A number is divisible by 5, if the digit at its unit's place is 0 or 5.

Consider the number 981547.

Unit digit of the number is 7. When 7 is divided by 5, the remainder obtained is 2.

Thus, 981547 when divided by 5 leaves the remainder 2.

2.

A number is divided by three, if the sum of its digit is divisible by 3.

Sum of digit of the number 51439786 = 5 + 1 + 4 + 3 + 9 + 7 + 8 + 6 = 43

43 is not divisible by 3. But, 43 – 1 = 42 is divisible by 3.

So, 51439785 is divisible by 3.

Thus, 51439786 when divided by 3, leaves the remainder 1.

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1 )  THE UNIT DIGIT OF A MUTIPLE OF 5 MUST BE 0 OR 5 . BUT IT IS 7 . SO , THE REMAINDER IS 7 - 5 =2 .

2 )  THE SUM OF THE DIGITS OF A MULTIPLE OF 3 MUST BE DIVISIBLE BY 3 . BUT IT IS 5 + 1 + 4 + 3 + 9 + 7 + 8 + 6 = 43 . WHEN 43 IS DIVIDED BY 3 THE REMAINDER IS 1 WHICH IS FOR 51439786 ALSO .

3 )  THE DIFFERENCE BETWEEN THE SUM OF ODD DIGITS AND THE SUM OF EVEN DIGITS FOR A MULTIPLE SHOULD BE 0 OR A MULTIPLE OF 11 . BUT IT IS ( 7 + 8 ) - 9 = 15 - 9 = 6 .SO , REMAINDER = 6 .

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