Write the first 5 terms of an AP whose nth term is given by (2n+1)/3.

Given, Tn = (2n + 1) /3
First term = (2*1 + 1) / 3 = 3/3 = 1
Second term = (2*2 + 1) / 3 = 5/3
Third term = (2*3 + 1) / 3 = 7/3
Fourth term = (2*4 + 1) / 3 = 9/3 = 3
Fifth term = (2*5 +1) / 3 = 11/3

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